Last modified on May 24th, 2024

chapter outline

 

Natural Logarithm

The natural logarithm (base-e-logarithm) of a positive real number x, represented by lnx or logex, is the exponent to which the base ‘e’ (≈ 2.718…, Euler’s number) is raised to obtain ‘x.’ 

Mathematically, ln(x) = loge(x) = y if and only if ey = x

Natural Logarithm

It is also written as:

lnx=1x1tdt

The number 2.718… is used naturally in math and science calculations, like pie (π) in geometry. 

Graphing

The geometric interpretation of the natural logarithmic function y = lnx is shown below.

Natural Logarithm Graph

Here, the natural logarithmic function has an asymptote at x = 0 and an x-intercept at (1, 0).

Proof

Now, let us verify the natural logarithm formula lnx=1x1tdt

According to the fundamental theorem of calculus, if F(x) is an antiderivative of f(x) for the interval [a, b], then abf(x)dx=f(b)f(a)

Now, let us find an antiderivative of f(t)=1t

1tdt=ln|t|+C, here c is the integrating constant.

Applying the fundamental theorem of calculus, we get

1x1tdt=ln|x|ln|1|

= ln|x|0

= ln|x|

Thus, 1x1tdt=ln|x|, is proved.

Rules

The natural logarithm follows all the properties of the logarithm. 

Product Rule

ln(xy) = lnx + lny

Example: ln(10) = ln(5) + ln(2)

Quotient Rule

ln(xy)=lnxlny

Example:  ln(425)=ln42ln5

Power Rule

ln(xn) = n lnx

Example:  ln((5z)7) = 7 ln(5z)

Change of Base Rule

lnx=logex=logbxlogbe

Or, lnx ⋅ logbe = logbx

Example: ln(2p2)=loge(2p2)=logb(2p2)logbe, for any base b

Identity Rule

ln(e) = 1

Zero Rule

ln(1) = 0

Infinity Rule

ln(∞) = ∞, which means while the argument ‘x’ approaches to infinity, the limit of ln(x) is:

lim ln(x) = ∞, when x → ∞

Derivative Rule

ddx(ln(x))=1x

Integration Rule

ln(x)dx=x(ln(x)1)+c

Others

  • ln of Negative Numbers: ln of any negative number is undefined.
  • ln of ‘0’ and the Limit: ln(0) is undefined, which means while the argument ‘x’ approaches zero, the limit of ln(0) is minus infinity. That is, lim ln(0) = -∞, when x → 0+
  • ln of ‘e’ raised to the power ‘x’: ln(ex) = x
  • ‘e’ raised to the ln power: eln(x) = x

Solved Example

Simplify: ln(e4x) + 4ln(x) – 2ln(2x)

Solution:

Here, ln(e4x) + 4ln(x) – 2ln(2x)
= 4x ln(e) + ln(x4) – ln((2x)2) (by the power rule of logarithm)
= 4x + ln(x4) – ln(4x2) (since ln(e) = 1)
= 4x+ln(x44x2) (by the quotient rule of logarithm)
= 4x+ln(x24)
= 4x+ln((x2)2)
= 4x+2ln(x2) (by the power rule of logarithm)
Thus, ln(e4x) + 4ln(x) – 2ln(2x) = 4x+2ln(x2)

Convert the natural logarithmic equation ln(15) = 2.708 (corrected to 3 decimal places) into its exponential form.

Solution:

As we know, ln(x) = y ⇔ ey = x
Here, ln(15) = 2.708Thus, e2.708 = 15

Last modified on May 24th, 2024