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Last modified on August 3rd, 2023

Irrational numbers are real numbers that cannot be written as a simple fraction or ratio. In simple words, the irrational numbers are those numbers those are not rational. Hippasus, a Greek philosopher and a Pythagorean, discovered the first evidence of irrational numbers 5th century BC. However, his theory was not accepted.

Irrational numbers can’t be written as p/q form (ratio), where the denominator, q is not zero (q â‰ 0).

Few examples of irrational numbers are given below:

- Ï€ (pi), the ratio of a circle’s circumference to its diameter, is an irrational number. It has a decimal value of 3.1415926535â‹…â‹…â‹…â‹… which doesn’t stop at any point.
- âˆšx is irrational for any integer x, where x is not a perfect square.

In a right triangle with a base length of 1 unit, the hypotenuse is âˆš2, which is irrational. (âˆš2 = 1â‹…414213â‹…â‹…â‹…â‹…)

- Euler’s number, e = 2â‹…718281â‹…â‹…â‹…â‹…
- Golden ratio, Ï† = 1.6180339â‹…â‹…â‹…â‹…

Given below are some popular irrational numbers.

Number | value |
---|---|

Pi (Ï€) | 3.1415926535â‹…â‹…â‹…â‹… |

Eulerâ€™s Number (e) | 2â‹…718281â‹…â‹…â‹…â‹… |

Golden ratio, Ï† | 1.6180339â‹…â‹…â‹…â‹… |

Let us solve an example

**${\dfrac{5\sqrt{2+4}}{\sqrt{3}}}$**

Solution:

${\begin{aligned}\dfrac{5\sqrt{2+4}}{\sqrt{3}}\\ \simeq \dfrac{5\sqrt{6}}{\sqrt{3}}\end{aligned}}$

= ${ 5\sqrt{2} }$

Irrational numbers are universally represented by the alphabet ‘P’. The universal symbols for rational numbers is ‘Q’, real numbers is ‘R’.

- Are real numbers only
- Decimal expansion is non-terminating (continues endlessly)
- Addition of a rational and irrational number gives an irrational number as the sum; a + b = irrational number, here a = rational number, b = irrational number
- Multiplication of a rational and irrational number will always give an irrational number; here, a Ã— b = irrational number, if a = rational number, b = irrational number
- Sum or product of 2 irrational numbers may give an irrational number; âˆš2 Ã— âˆš2 = 2.
- The Least common factor (LCM) for 2 irrational numbers may or may not exist

Let us solve some examples to understand the concept better.

**Ï€ Ã— Ï€**

Solution:

Let us see if Ï€ Ã— Ï€ = rational or irrational

Ï€ Ã— Ï€

= Ï€^{2}

= irrational, âˆµ Ï€ is irrational

**âˆš7 Ã— âˆš7**

Solution:

âˆš7 Ã— âˆš7

= 7

= rational

**Show that âˆš7 + âˆš5 is irrational.**

Solution:

Let us assume that âˆš7 + âˆš5 is rational

If âˆš7 + âˆš5 is rational,

Then, ${\dfrac{7-5}{\sqrt{7}+\sqrt{5}}=\sqrt{7}-\sqrt{5} }$ , implying âˆš7 – âˆš5 is also rational

(âˆš7 + âˆš5) – (âˆš7 – âˆš5)

= 2âˆš5, (implies 2âˆš5 is rational)

Hence, ${2\sqrt{5}\times \dfrac{1}{2}}$

= âˆš5 is also rational. But this is a contradiction

Hence, we get the proof of irrational numbers by contradiction

We already have learnt that irrational numbers are real numbers which cannot be represented in the form of p/q, where p and q are integers, and q â‰ 0, and also can’t be simplified to a closed decimal value.

Taking âˆš5 as an example,

It cannot be represented in the form of a fraction

It cannot be simplified either. Its value is 2.236067â‹…â‹…â‹…â‹… and it is not a closed decimal value.

Thus, âˆš5 is irrational.

Rational numbers are numbers that can be expressed in the form of a fraction (p/q) or ratio.

Given below the differences between rational and irrational numbers in a table.

Irrational Numbers | Rational Numbers |
---|---|

Cannot be expressed in the form of a fraction (p/q) | Can be expressed in the form of a fraction (p/q) |

The decimal expansion is non-terminating (continues endlessly) and non-recurring (with no group of digits repeating) at any point | The decimal expansion is terminating (ends at some point) or non-terminating recurring (repeating) |

Last modified on August 3rd, 2023

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Hey there! Wonderful little article, it explains things pretty clearly and introduces concepts that seem worth looking into, particularly the properties of irrational numbers. However, I find a lot of confusion with property #4, it seems to be incorrect. See this simple proof by contradiction: https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:irrational-numbers/x2f8bb11595b61c86:sums-and-products-of-rational-and-irrational-numbers/v/proof-that-rational-times-irrational-is-irrational

There isn’t any example showcasing this property either in the examples section either, so I’m just assuming it was written in error. Would appreciate a response clearing up the confusion or a correction of the error if it is one, thank you!!

Thank you for your comment. We have edited that section.