Table of Contents
Last modified on August 3rd, 2023
A pyramid is a three-dimensional solid object with a flat base and a pointed end.
The base can be of any shape such as triangle, square, rectangle, or a pentagon. The diagram above shows a pyramid with a square base.
The Pyramids of Giza, in Egypt, is a very common and beautiful example of a pyramid shape.
A pyramid is a polyhedron with a polygonal base bounded by triangular faces meeting at a common vertex, known as the apex. The triangular faces are called the lateral faces.
When a pyramid is rested on its base, it points upwards. The square pyramid is the most common type of pyramid.
A pyramid has an apex, vertices, a base, lateral faces, and edges.
Depending on the base, a pyramid can be of different shapes. Some common types are: triangular, rectangular, square, pentagonal, hexagonal.
How many edges, faces, sides, and vertices does a pyramid have?
A pyramid with n-sided bases, has n + 1 faces, n + 1 vertices, and 2n edges. For example, a triangular pyramid has 4 faces (1 triangular base and 3 triangular lateral faces), 4 vertices, and 6 edges.
A pyramid can be right or oblique, depending on the location of its apex.
A pyramid can also be regular or irregular, depending on the regularity of its base.
Like all other polyhedrons, we can also calculate the surface area and volume of a regular pyramid.
Surface Area (SA) = ${B+\dfrac{1}{2}Ps}$, here B = base area, P = base perimeter, s = slant height,
Also ${\dfrac{1}{2}P{s}}$ = lateral surface area (LSA)
∴ SA = B + LSA
Let us solve some examples to understand the above concept better.
Find the lateral and total surface area of a square pyramid with a base area of 64 cm2, base perimeter of 32 cm, and slant height of 8.5 cm.
As we know,
Lateral Surface Area (LSA) = ${\dfrac{1}{2}P{s}}$, here P = 32 cm, s = 8.5 cm
∴ LSA = ${\dfrac{1}{2}\times 32\times 8\cdot 5}$
= 136 cm2
Total Surface Area (TSA) = B + LSA, here B = 64 cm2, LSA = 136 cm2
∴ TSA = 64 + 136
= 200 cm2
Find the total surface area of a triangular pyramid with a base area of 7.3 cm2, base perimeter of 12.3 cm, and slant height of 6 cm.
As we know,
Total Surface Area (TSA) = ${B+\dfrac{1}{2}Ps}$, here B = 7.3 cm2, P = 12.3 cm, s = 6 cm
∴ TSA = ${7.3+\dfrac{1}{2}\times 12.3\times 6}$
= 44.2 cm2
The formula is given below:
Volume (V) = ${\dfrac{1}{3}Bh}$, here B = base area, h = height
Let us solve an example to understand the above concept better.
Find the volume of a square pyramid with a base area of 49 cm2, and a height of 12 cm.
As we know,
Volume (V) = ${\dfrac{1}{3}Bh}$, here B = 49 cm2, h = 12 cm
∴ V = ${\dfrac{1}{3}\times 49\times 12}$
= 196 cm3
Last modified on August 3rd, 2023
Well written, easy to follow, a wonderful resource. Thanks.
Hi, there. I was just wondering about horizontal cross-sections of oblique square based pyramids. Will the horizontal cross-section always be a square…as it will always be with a right square based pyramid? Thanks so much.
Horizontal cross-sections of an oblique square-based pyramid will not always be squares. The shape of the cross-section will depend on the angle of the slant of the pyramid’s sides and the height at which the cross-section is made.
It was very helpful for me ☺️ and easy to understand, keep it up mathmonks…