Table of Contents
Last modified on October 28th, 2024
An exponent refers to the power a number is raised to. For example, the number 5 raised to the power of 3 is 53, which means 5 × 5 × 5 = 125
In an exponential function, the output depends on an expression where the variable appears in the exponent. For example, y = 5x is an exponential function as the variable x is in the exponent to base 5.
Exponential functions are nonlinear because their slopes are always changing. They appear as curves rather than straight lines on their graphs.
A graph of an exponential function will always reach positive or negative infinity on one end and approach but never reach a horizontal line on the other. The horizontal line that the graph approaches but never reaches is called the horizontal asymptote.
An exponential function can be of two types. It is either always increasing or always decreasing. Accordingly, they are called Exponential Growth Function and Exponential Decay Function, respectively.
If f(1) > f(0), then the slope of the graph is positive and is thus an exponential growth function.
Let us graph the exponential function f(x) = 5x
Step 1: Choosing Values of x
x | f(x) |
---|---|
-2 | 0.04 |
-1 | 0.2 |
0 | 1 |
1 | 5 |
2 | 25 |
The output values in the table change as the input increases by 1.
Step 2: Plotting the Points
Now, plotting the points in the graph, we get
The graph shows that y = 5x is an increasing function, which means it increases as x increases and is thus an exponential growth function.
Slope
Since f(1) > f(0), the slope of the above graph is positive.
Domain
The domain consists of all real numbers. Thus, it is written in interval notation as (-∞, ∞)
End Behaviour
The value of y on the right end of the graph approaches infinity. Thus, the range is (0, ∞)
Horizontal Asymptote
The horizontal asymptote of the function is the x-axis (i.e., y = 0)
Graph y = 2x
Choosing the values for x,
x | y |
---|---|
-2 | 0.25 |
-1 | 0.5 |
0 | 1 |
1 | 2 |
2 | 4 |
After plotting the points, we get the required graph.
The graph shows that y = 2x is an increasing function, which means it increases as x increases and is thus an exponential growth function.
If f(1) < f(0), then the slope of the graph is negative and is thus an exponential decay function.
Let us graph the exponential function f(x) = 5-x
Step 1: Choosing Values of x
x | f(x) |
---|---|
-1 | 5 |
0 | 1 |
1 | 0.2 |
2 | 0.04 |
3 | 0.008 |
Step 2: Plotting the Points
Now, plotting the points in the graph, we get
The graph shows that y = 5-x is a decreasing function, which means it decreases as x increases and is thus an exponential decay function.
Slope
Since f(1) < f(0), the above graph is negative.
Domain
The domain consists of all real numbers. Thus, it is written in interval notation as (-∞, ∞)
End Behaviour
The value of y on the left end of the graph approaches infinity. Thus, the range is (0, ∞)
Horizontal Asymptote
The horizontal asymptote of the function is the x-axis (i.e., y = 0)
Graph y = 2-x
Choosing the values for x,
x | y |
---|---|
-2 | 0.25 |
-1 | 0.5 |
0 | 1 |
1 | 2 |
2 | 4 |
After plotting the points, we get the required graph.
The graph shows that y = 2-x is a decreasing function, which means it decreases as x increases and is thus an exponential decay function.
As with other parent functions, exponential graphs can be transformed by shifting, reflecting, stretching, and compressing relative to the parent function f(x) = bx
For the parent function f(x) = bx, vertical translation shifts the graph up or down by adding or subtracting a constant d to the equation. The translated equation becomes
Here, the parent function f(x) = 5x is shifted 3 units up and 3 units down. The translated equation becomes f(x) = 5x + 3 and f(x) = 5x – 3 respectively.
The domain (-∞, ∞) remains unchanged. The range for f(x) = 5x + 3 is (3, ∞) and the range for f(x) = 5x – 3 is (-3, ∞)
For the parent function f(x) = bx, horizontal translation shifts the graph to the left or right by adding or subtracting a constant d to the exponent. The translated equation becomes
The domain (-∞, ∞) remains unchanged.
A stretch or compression occurs when we multiply the parent function f(x) = bx by a constant |a| > 0
Here,
f(x) = 2(5x) stretches the parent function to f(x) = 5x
f(x) = ${\dfrac{1}{2}\left( 5^{x}\right)}$ compresses the parent function to f(x) = 5x
Exponential functions can also be reflected along the x-axis or the y-axis.
Here, the parent function f(x) = 2x is reflected along the x and the y-axis.
Given the exponential function f(x) = 3x, describe the transformations for the following functions and sketch their graphs:
a) g(x) = 3x + 5
b) h(x) = 3x – 4
c) j(x) = -3x + 5
d) k(x) = 3 · 3x – 2
Given the exponential function is f(x) = 3x
a) As we know, the horizontal shift of the parent function f(x) = bx gives the translated equations:
Here, g(x) = 3x + 5 represents the horizontally shifted function 5 units to the left relative to the parent function f(x) = 3x
After plotting them, we get the required graph.
b) As we know, the vertical shift to the parent function f(x) = bx gives the translated equations:
Here, h(x) = 3x – 4 represents the vertically shifted function 4 units downward relative to the parent function f(x) = 3x
After plotting them, we get the required graph.
c) As we know, the vertical shift to the parent function f(x) = bx gives the translated equations:
Also, if we multiply the parent function f(x) = bx by –1, it is reflected along the x-axis.
Here, j(x) = -3x + 5 has a negative sign in front of 3x and is in the form j(x) = -bx + d
Thus, j(x) = -3x + 5 is a reflection of the parent function f(x) = 3x along the x-axis. It is then vertically shifted up by 5 units.
After plotting them, we get the required graph.
d) As we know, the horizontal shift to the parent function f(x) = bx gives the translated equations:
Also, if we multiply the parent function by a constant a (here, a > 0), it stretches f(x), and the translated equation becomes f(x) = abx
Here, k(x) = 3 · 3x – 2 vertically stretches the graph, making it steeper than the original function f(x) = 3x. It is then horizontally shifted 2 units to the right relative to f(x).
Last modified on October 28th, 2024