Table of Contents
Last modified on November 19th, 2024
Exponents and square roots are inversely related operations. While exponents involve raising a number to a power, square roots inverse this operation by finding the original base that, when squared, gives the result.
For example,
8 to the 2nd power is 82 = 64, which means 8 is multiplied by itself 2 times. When exponents are used, the results grow very rapidly.
Now, to find the square root of 64, we need a number that, when squared (multiplied by itself), equals 64. That number is 8, so the square root of 64 is 8.
When converting an exponent into a square root, the base, say x, is raised to the fractional exponent, ${x^{\dfrac{1}{2}}}$, which represents the square root of that base. It can be expressed as
${x^{\dfrac{1}{2}}=\sqrt{x}}$
In general, raising a base to the power of ${\dfrac{1}{n}}$ corresponds to finding the nth root of the base.
For example,
${9^{\dfrac{1}{2}}=\sqrt{9}=3}$
To express a square root as an exponent, the base under the radical is rewritten with a fractional exponent. It is expressed as
${\sqrt{x}=x^{\dfrac{1}{2}}}$
More generally, an nth root is written using a fractional exponent: ${\sqrt[n] {x}=x^{\dfrac{1}{n}}}$
For example,
${\sqrt{9}=9^{\dfrac{1}{2}}}$
However, to simplify complex problems involving these conversions, we need to follow certain rules.
Here are the rules for simplifying expressions involving both square roots and exponents.
Simplify: ${\sqrt{x^{4}}}$
Here, ${\sqrt{x^{4}}}$
Converting the square root into an exponent,
${x^{\dfrac{4}{2}}}$
= x2
Thus, ${\sqrt{x^{4}}}$ = x2
Simplify: ${\sqrt{16x^{6}}}$
Here, ${\sqrt{16x^{6}}}$
Using the product rule for radicals,
${\sqrt{16}\times \sqrt{x^{6}}}$
= ${4x^{\dfrac{6}{2}}}$
= ${4x^{3}}$
Thus, ${\sqrt{16x^{6}}}$ = ${4x^{3}}$
Solve: ${\dfrac{\sqrt{x^{5}}}{\sqrt{x^{2}}}}$
Here, ${\dfrac{\sqrt{x^{5}}}{\sqrt{x^{2}}}}$
Using the quotient rule for square roots,
${\sqrt{\dfrac{x^{5}}{x^{2}}}}$
= ${\sqrt{x^{5-2}}}$
= ${\sqrt{x^{3}}}$
= ${x^{\dfrac{3}{2}}}$
Thus, ${\dfrac{\sqrt{x^{5}}}{\sqrt{x^{2}}}}$ = ${x^{\dfrac{3}{2}}}$
Simplify the expression: ${\left( \sqrt{x^{6}}\right) ^{2}}$
Here, ${\left( \sqrt{x^{6}}\right) ^{2}}$
Using the power of a root rule,
= ${\left( \left( x^{6}\right) ^{\dfrac{1}{2}}\right) ^{2}}$
= ${\left( x^{\dfrac{6}{2}}\right) ^{2}}$
= ${\left( x^{3}\right) ^{2}}$
= ${x^{3\times 2}}$
= ${x^{6}}$
Thus, ${\left( \sqrt{x^{6}}\right) ^{2}}$ = ${x^{6}}$
Last modified on November 19th, 2024