Table of Contents
Last modified on August 28th, 2024
Adding fractions involves three basic steps:
To add fractions with like denominators, we just add the numerators and then write the sum over the common denominator.
Let us add the fractions ${\dfrac{2}{7}+\dfrac{4}{7}}$
Identifying the Denominators
Here, the denominators are 7
Adding the Numerators
${\dfrac{2+4}{7}}$
= ${\dfrac{6}{7}}$, which cannot be simplified or reduced further.
Thus, the sum is ${\dfrac{6}{7}}$
Let us add the unlike fractions ${\dfrac{2}{15}+\dfrac{1}{6}}$
Identifying the Denominators
Here, the denominators are 15 and 6, that are different.
Finding the LCM of the Denominators
The LCM of 15 and 6 is 30
Making the Denominators the Same
Converting ${\dfrac{2}{15}}$ and ${\dfrac{1}{6}}$ to their equivalent fractions with 30 as the denominator,
${\dfrac{2\times 2}{15\times 2}}$ = ${\dfrac{4}{30}}$
${\dfrac{1\times 5}{6\times 5}}$ = ${\dfrac{5}{30}}$
Now, we have ${\dfrac{4}{30}+\dfrac{5}{30}}$
Adding the Numerators
On adding the numerators,
${\dfrac{4+5}{30}}$
= ${\dfrac{9}{30}}$
Simplifying
${\dfrac{9\div 3}{30\div 3}}$
= ${\dfrac{3}{10}}$
Thus, the sum is ${\dfrac{3}{10}}$
Add: ${\dfrac{7}{9}}$ and ${\dfrac{11}{3}}$
Here, the denominators are 9 and 3
The LCM of 9 and 3 is 9
Now, ${\dfrac{7}{9}+\dfrac{11}{3}}$
= ${\dfrac{7}{9}+\dfrac{11\times 3}{3\times 3}}$
= ${\dfrac{7}{9}+\dfrac{33}{9}}$
= ${\dfrac{7+33}{9}}$
= ${\dfrac{40}{9}}$
= ${4\dfrac{4}{9}}$
Thus, the sum is ${4\dfrac{4}{9}}$
Problem: Adding a NEGATIVE FRACTION
Add: ${\dfrac{5}{12}+\left( \dfrac{-1}{6}\right)}$
Here, the denominators are 12 and 6
The LCM of 12 and 6 are 12
Now, ${\dfrac{5}{12}+\left( \dfrac{-1}{6}\right)}$
= ${\dfrac{5}{12}+\left( \dfrac{-1\times 2}{6\times 2}\right)}$
= ${\dfrac{5}{12}+\left( \dfrac{-2}{12}\right)}$
= ${\dfrac{5-2}{12}}$
= ${\dfrac{3}{12}}$
= ${\dfrac{1}{4}}$
Thus, the sum is ${\dfrac{1}{4}}$
Co-prime denominators are the denominators with no common factors between them other than 1.
Given, ${\dfrac{2}{7}+\dfrac{1}{5}}$
Identifying the Denominators
First, we identify the denominators and determine whether they are co-prime.
Here, the denominators are 7 and 5, that are co-prime.
Multiplying the First Fraction By the Denominator of the Second Fraction and Vice-Versa
${\dfrac{2\times 5}{7\times 5}+\dfrac{1\times 7}{5\times 7}}$
= ${\dfrac{10}{35}+\dfrac{7}{35}}$
Adding the Numerators
${\dfrac{10+7}{35}}$
= ${\dfrac{17}{35}}$
Thus, the sum is ${\dfrac{17}{35}}$
Let us add: ${5+\dfrac{3}{8}}$
Converting the Whole Number to Fraction
${5}$ = ${\dfrac{5}{1}}$
Now, we have ${\dfrac{5}{1}+\dfrac{3}{8}}$
Identifying the Denominators
The denominators are 1 and 8, which are different.
Finding the LCM of the Denominators
The LCM of 1 and 8 is 8
Adding the Numerators
${\dfrac{5\times 8}{1\times 8}+\dfrac{3\times 1}{8\times 1}}$
= ${\dfrac{40}{8}+\dfrac{3}{8}}$
= ${\dfrac{40+3}{8}}$
= ${\dfrac{43}{8}}$
= ${5\dfrac{3}{8}}$
However, a simple way to add a whole number to a proper fraction is to combine and express them as a mixed number.
For example, ${5+\dfrac{3}{8}}$ is written as ${5\dfrac{3}{8}}$
To add fractions with mixed numbers, we convert the mixed numbers into improper fractions and then add them.
If ${\dfrac{5}{8}+1\dfrac{3}{10}}$
Converting to Improper Fraction
Converting ${1\dfrac{3}{10}}$ to improper fraction,
${1\dfrac{3}{10}}$ = ${\dfrac{\left( 1\times 10\right) +3}{10}}$ = ${\dfrac{13}{10}}$
Identifying the Denominators
Here, the denominators are 8 and 10
Finding the LCM of the Denominators
The LCM of 8 and 10 is 40
Making the Denominators the Same and Adding the Numerators
${\dfrac{5\times 5}{8\times 5}+\dfrac{13\times 4}{10\times 4}}$
= ${\dfrac{25}{40}+\dfrac{52}{40}}$
= ${\dfrac{25+52}{40}}$
= ${\dfrac{77}{40}}$
= ${1\dfrac{37}{40}}$
Thus, the sum is ${1\dfrac{37}{40}}$
Find the sum of ${2\dfrac{1}{4}+\dfrac{1}{5}}$
Here, the denominators are 4 and 5
The LCM of 4 and 5 is 20
Also, ${2\dfrac{1}{4}}$ = ${\dfrac{\left( 2\times 4\right) +1}{4}}$ = ${\dfrac{9}{4}}$
Now, ${2\dfrac{1}{4}+\dfrac{1}{5}}$
= ${\dfrac{9}{4}+\dfrac{1}{5}}$
= ${\dfrac{9\times 5}{4\times 5}+\dfrac{1\times 4}{5\times 4}}$
= ${\dfrac{45}{20}+\dfrac{4}{20}}$
= ${\dfrac{45+4}{20}}$
= ${\dfrac{49}{20}}$
= ${2\dfrac{9}{20}}$
Thus, the sum is ${2\dfrac{9}{20}}$
Now, let us add fractions, including variables.
If ${\dfrac{p}{2}+\dfrac{2p}{5}}$
Identifying the Denominators
The denominators are 2 and 5
Finding the LCM of the Denominators
The LCM of 2 and 5 is 10
Making the Denominators the Same and Adding the Numerators
${\dfrac{p\times 5}{2\times 5}+\dfrac{2p\times 2}{5\times 2}}$
= ${\dfrac{5p}{10}+\dfrac{4p}{10}}$
= ${\dfrac{5p+4p}{10}}$
= ${\dfrac{9p}{10}}$
Thus, the sum is ${\dfrac{9p}{10}}$
Last modified on August 28th, 2024