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Last modified on August 20th, 2024

Ordering fractions is arranging a group of fractions from least to greatest (ascending order) or from greatest to least (descending order).

Based on whether the fractions have the same denominator, different denominator, or different numerator and denominator, the steps for ordering vary.

Let us order the fractions ${\dfrac{1}{9},\dfrac{7}{9},\dfrac{5}{9},\dfrac{4}{9},\dfrac{13}{9}}$ from greatest to least and least to greatest.

**Identifying the Denominators**

Here, the denominator is 9

Since the fractions have the same denominator, we can compare the numerators directly.

**Comparing the Numerators**

13 > 7 > 5 > 4 > 1

This gives the fractions from the highest to the lowest value. As a result, the least numerator gives the least fraction, and vice versa.

**Ordering the Fractions**

Ordering from greatest to least, we get

${\dfrac{13}{9} >\dfrac{7}{9} >\dfrac{5}{9} >\dfrac{4}{9} >\dfrac{1}{9}}$

Ordering from least to greatest, we get

${\dfrac{1}{9} <\dfrac{4}{9} <\dfrac{5}{9} <\dfrac{7}{9} <\dfrac{13}{9}}$

**E.g.1. **

**Order the fractions from greatest to least: ${\dfrac{2}{5},\dfrac{4}{5},\dfrac{1}{5},\dfrac{3}{5}}$****Identifying the Denominators**

Solution:

Here, the denominators of fractions are 5, which is the same.**Comparing the Numerators**

1 > 2 > 3 > 4**Ordering the Fractions**

On ordering the fractions, we get

${\dfrac{4}{5} >\dfrac{3}{5} >\dfrac{2}{5} >\dfrac{1}{5}}$

Now, let us order the following fractions having the same numerator ${\dfrac{7}{4},\dfrac{7}{2},\dfrac{7}{5},\dfrac{7}{3}}$

**Identifying the Denominators**

Here, the numerators of fractions are 7, which is the same.

**Comparing the Denominators**

5 > 4 > 3 > 2

This gives the fractions from the lowest to the highest value. As a result, the least denominator gives the highest fraction, and vice versa.

**Ordering the Fractions**

Ordering from greatest to least, we get

${\dfrac{7}{2} >\dfrac{7}{3} >\dfrac{7}{4} >\dfrac{7}{5}}$

Ordering from least to greatest, we get

${\dfrac{7}{5} <\dfrac{7}{4} <\dfrac{7}{3} >\dfrac{7}{2}}$

**Arrange the fractions in ascending order: ${\dfrac{5}{2},\dfrac{5}{7},\dfrac{5}{4},\dfrac{5}{8}}$****Identifying the Denominators**

Solution:

Here, the numerators of fractions are 5, which is the same.**Comparing the Denominators**

8 > 7 > 4 > 2**Ordering the Fractions**

The fractions in ascending order are as follows:

${\dfrac{5}{8} <\dfrac{5}{7} <\dfrac{5}{4} <\dfrac{5}{2}}$

**Problem – **Ordering **UNIT FRACTIONS**

**Arrange the fractions in ascending order:****${\dfrac{1}{2},\dfrac{1}{7},\dfrac{1}{3},\dfrac{1}{13}}$****Identifying the Denominators**

Solution:

Here, the numerators of fractions are 1, which is the same.**Comparing the Denominators**

13 > 7 > 3 > 2**Ordering the Fractions**

The fractions in ascending order are as follows:

${\dfrac{1}{13} <\dfrac{1}{7} <\dfrac{1}{3} <\dfrac{1}{2}}$

To order fractions with different denominators and numerators, we need to make the denominators the same. That is achieved by converting them to equivalent fractions.

If we order the fractions ${\dfrac{2}{3},\dfrac{5}{9},\dfrac{1}{2},\dfrac{3}{4}}$

**Identifying the Denominators**

Here, the numerators and denominators are all different.

**Converting them into Equivalent Fractions **

The denominators are 3, 9, 2, and 4. Their LCM is 36

Now, the fractions with a common denominator are

${\dfrac{2\times 12}{3\times 12}=\dfrac{24}{36}}$

${\dfrac{5\times 4}{9\times 4}=\dfrac{20}{36}}$

${\dfrac{1\times 18}{2\times 18}=\dfrac{18}{36}}$

${\dfrac{3\times 9}{4\times 9}=\dfrac{27}{36}}$

**Comparing the Numerators **

27 > 24 > 20 > 18

**Ordering the Fractions **

Now, writing the fractions in descending order,

${\dfrac{3}{4} >\dfrac{2}{3} >\dfrac{5}{9} >\dfrac{1}{2}}$

Also, in ascending order,

${\dfrac{1}{2} <\dfrac{5}{9} <\dfrac{2}{3} >\dfrac{3}{4}}$

**Order the fractions from least to greatest: ****${\dfrac{3}{5},\dfrac{7}{8},\dfrac{4}{7}}$****Identifying the Denominators**

Solution:

Here, the numerators and denominators are all different.**Converting them into Equivalent Fractions **

The denominators are 5, 8, and 7. Their LCM is 280

Now, the fractions with a common denominator are

${\dfrac{3\times 56}{5\times 56}=\dfrac{168}{280}}$

${\dfrac{7\times 35}{8\times 35}=\dfrac{245}{280}}$

${\dfrac{4\times 40}{7\times 40}=\dfrac{160}{280}}$**Comparing the Numerators **

245 > 168 > 160**Ordering the Fractions **

Ordering the fractions from least to greatest, we get

${\dfrac{4}{7} <\dfrac{3}{5} <\dfrac{7}{8}}$

Last modified on August 20th, 2024