Table of Contents
Last modified on October 15th, 2024
The standard form and vertex form are two different ways to express the equation of a parabola. Converting between these forms is useful for solving mathematical problems and performing statistical analysis, depending on which form makes the task easier.
y = ax2 + bx + c
x = ay2 + by + c
Here,
If a > 0, the parabola opens upwards, and if a < 0, the parabola opens downwards.
The standard forms are used to identify the direction in which the parabola opens and determine the y-intercept (c).
y = a(x – h)2 + k
x = a(y – k)2 + h
Here,
The parabola opens upwards if a > 0, and it opens downwards if a < 0
The vertex forms are used to identify the vertex (h, k) of the parabola, making it easier to graph and determine its maximum or minimum point.
Equations in standard form can be converted to their corresponding vertex form either by completing the square method or by using the vertex.
Let us convert the parabola y = 2x2 + 8x + 7 to its vertex form by the method of completing the square.
Factoring out the GCF
⇒ y = 2(x2 + 4x) + 7
Simplifying
To complete the square, we add and subtract 8 on the right side of the equation.
⇒ y = 2(x2 + 4x) + 7 + 8 – 8
⇒ y = 2(x2 + 4x + 4) + 7 – 8
⇒ y = 2(x + 2)2 – 1
Thus, the equation in vertex form is y = 2(x + 2)2 – 1….(i), which is of the form y = a(x – h)2 + k ….(ii)
Now, on comparing equation (i) with (ii), we get
a = 2, h = -2, and k = -1 and the vertex is at (-2, -1)
As we know, in the standard form of the parabola y = ax2 + bx + c, the vertex (h, k) is given by the formula:
Now, let us convert y = 2x2 + 8x + 7 to its vertex form by using these formulas.
Comparing
Comparing the equation with the standard form of the parabola y = ax2 + bx + c, we get
a = 2, b = 8, and c = 7 …..(i)
Finding the Vertex
h = ${-\dfrac{b}{2a}}$ = ${-\dfrac{8}{2\times 2}}$ = -2
k = f(-2) = 2(-2)2 + 8(-2) + 7 = -1
Thus, the vertex is at (-2, -1) …..(ii)
Substituting
Now, substituting the values of (i) and (ii) in the vertex form y = a(x – h)2 + k, we get
y = 2(x + 2)2 – 1
Thus, the equation in vertex form is y = 2(x + 2)2 – 1
Now, we will convert the parabola y = 2(x + 2)2 – 1 to its corresponding standard form.
Expanding
y = 2(x + 2)(x + 2) – 1
⇒ y = 2(x2 + 4x + 4) – 1
Simplifying
⇒ y = 2x2 + 8x + 8 – 1
⇒ y = 2x2 + 8x + 7….(i), which is of the form y = ax2 + bx + c ….(ii)
Now, on comparing equation (i) with (ii), we get
a = 2, b = 8, and c = 7, and the vertex is at (0, 0)
What is the vertex form of the quadratic equation y = 3x2 – 12x + 5
Given y = 3x2 – 12x + 5
⇒ y = 3(x2 – 4x) + 5
⇒ y = 3(x2 – 4x + 4) + 5
⇒ y = 3(x – 2)2 + 5
Thus, the vertex form of the equation is y = 3(x – 2)2 + 5
Convert the equation y = -5(x – 2)2 + 20 to its standard form.
Given y = = -5(x – 2)2 + 20
⇒ y = -5(x2 – 4x + 4) + 20
⇒ y = -5x2 + 20x – 20 + 20
⇒ y = -5x2 + 20xThus, the standard form of the equation is y = -5x2 + 20x
Last modified on October 15th, 2024