Table of Contents
Last modified on January 16th, 2025
Trigonometric identities are equations involving trigonometric functions that hold true for all values of the variables within their domains.
There are many such identities, either involving the sides of a right-angled triangle, its angle, or both. They are based on the six fundamental trigonometric functions: sine (sin), cosine (cos), tangent (tan), cosecant (cosec), secant (sec), and cotangent (cot).
All the identities are derived from the six trigonometric functions and are used to simplify expressions, verify equations, and solve trigonometric problems.
Trigonometric identities are classified based on the type of relationships they describe among trigonometric functions.
These identities express the reciprocal relationships between sine, cosine, tangent, and their corresponding co-functions.
There are 3 Pythagorean identities in trigonometry, and they are based on the right-angled triangle rule or Pythagorean theorem.
Let us consider a right-angled triangle ABC, which is right-angled at C, as shown.
By applying the Pythagoras theorem to this triangle, we get
Opposite2 + Adjacent2 = Hypotenuse2 …..(i)
On dividing both sides of equation (i) by Hypotenuse2, we get
${\dfrac{Opposite^{2}}{Hypotenuse^{2}}+\dfrac{Adjacent^{2}}{Hypotenuse^{2}}=\dfrac{Hypotenuse^{2}}{Hypotenuse^{2}}}$
From the definitions of the trigonometric ratios,
⇒ sin2 θ + cos2 θ = 1
As we know from the right-angled triangle rule,
Opposite2 + Adjacent2 = Hypotenuse2 …..(i)
Dividing both sides of equation (i) by Adjacent2, we get
${\dfrac{Opposite^{2}}{Adjacent^{2}}+\dfrac{Adjacent^{2}}{Adjacent^{2}}=\dfrac{Hypotenuse^{2}}{Adjacent^{2}}}$
From the definitions of the trigonometric ratios,
⇒ 1 + tan2 θ = sec2 θ
Similarly,
Dividing both sides of equation (i) by Opposite2, we get
${\dfrac{Opposite^{2}}{Opposite^{2}}+\dfrac{Adjacent^{2}}{Opposite^{2}}=\dfrac{Hypotenuse^{2}}{Opposite^{2}}}$
By using the definitions of the trigonometric ratios,
⇒ 1 + cot2 θ = cosec2 θ
These identities define tangent and cotangent in terms of sine and cosine:
Complementary identities (also known as co-function identities) show how the function of an angle θ relates to the co-function of its complement angle (90° – θ):
These identities represent how the trigonometric values of an angle θ are related to its supplementary angle (180° – θ):
Even-odd identities describe the behavior of trigonometric functions for opposite angles (−θ) and highlight their symmetry properties. These identities classify trigonometric functions as either even or odd based on how their values change with the sign of the angle.
Trigonometric functions are periodic, which means they repeat themselves after a regular interval, called periods. Each function has a different period.
Here, n ∈ ℤ (set of all integers)
Note: The sine, cosine, and their reciprocals (cosecant and secant) functions have a period of 2π or 360°. Moreover, the tangent and cotangent functions have a period of π or 180°.
The identities involving the sum or difference of two angles for the sine, cosine, and tangent functions are as follows:
If the angles of the six trigonometric functions are doubled, then the identities are:
If the angles of the six trigonometric functions are halved, then the identities are:
When the angle of a trigonometric function is three times a given angle (3θ), the corresponding identities are:
The product-to-sum identities express products of trigonometric functions as their sums or differences:
The sum-to-product identities express sums of trigonometric functions as products of those functions:
These identities are applicable for all the triangles, not just for the right triangles.
If A, B, and C are the vertices of a given triangle and a, b, and c are its corresponding sides, then:
Or
Or
Or
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Or
Simplify the expression ${\dfrac{\sin ^{2}\theta }{1-\cos \theta }+\dfrac{\sin ^{2}\theta }{1+\cos \theta }}$
Given, ${\dfrac{\sin ^{2}\theta }{1-\cos \theta }+\dfrac{\sin ^{2}\theta }{1+\cos \theta }}$
= ${\dfrac{\sin ^{2}\theta \left( 1+\cos \theta \right) +\sin ^{2}\theta \left( 1-\cos \theta \right) }{\left( 1+\cos \theta \right) \left( 1-\cos \theta \right) }}$
= ${\dfrac{\sin ^{2}\theta \left( 1+\cos \theta +1-\cos \theta \right) }{1-\cos ^{2}\theta }}$
As we know from the Pythagorean identities, 1 – cos2 θ = sin2 θ
= ${\dfrac{2\sin ^{2}\theta }{\sin ^{2}\theta }}$
= ${2}$
Prove the given identity:
${\dfrac{\sin ^{3}\theta +\cos ^{3}\theta }{\sin \theta +\cos \theta }+\sin \theta \cos \theta =1}$
As we know, the sum of cubes formula: a3 + b3 = (a + b)(a2 – ab + b2)
For a = sin θ and b = cos θ, we get
sin3 θ + cos3 θ = (sin θ + cos θ)(sin2 θ – sin θ cos θ + cos2 θ) …..(i)
Given, ${\dfrac{\sin ^{3}\theta +\cos ^{3}\theta }{\sin \theta +\cos \theta }+\sin \theta \cos \theta }$
By using (i), we get
= sin2 θ – sin θ cos θ + cos2 θ + sin θ cos θ
As we know from the Pythagorean identities, sin2 θ + cos2 θ = 1
= 1 – sin θ cos θ + sin θ cos θ
= 1
Thus, the given identity is proved.
Prove the identity:
(sec θ + cosec θ)2 – (tan2 θ + cot2 θ) = 2(1 + sec θ cosec θ)
Given, (sec θ + cosec θ)2 – (tan2 θ + cot2 θ) = 2(1 + sec θ cosec θ)
Expanding the left-hand-side,
(sec θ + cosec θ)2 – (tan2 θ + cot2 θ)
= sec2 θ + cosec2 θ + 2sec θ cosec θ – tan2 θ – cot2 θ
As we know from the Pythagorean identities, sec2 θ = 1 + tan2 θ and cosec2 θ = 1 + cot2 θ
= 1 + tan2 θ + 1 + cot2 θ + 2sec θ cosec θ – tan2 θ – cot2 θ
= 1 + 1 + 2sec θ cosec θ
= 2 + 2sec θ cosec θ
= 2(1 + sec θ cosec θ)
Thus, the given identity is proved.
Last modified on January 16th, 2025