Table of Contents

Last modified on August 3rd, 2023

Take a round-shaped paper and fold it in half. Have you noticed the shape you got? It is called a semicircle. It is thus half the circumference of the full circle. Semicircle is one of the most common shapes, we find in our real life. A protractor, a speedometer, a taco are all examples of semicircles.

‘Semi’ means half, thus semicircle is a half-circle. It is formed when a line passing through the center of the circle touches the two ends forming an intercepted arc.

Thus a semicircle consists of the diameter of the circle and its connecting arc. Semicircle being half a circle, its arc always measures (360°/2 = 180°) and thus is referred to as a half-disc. It has only one line symmetry, the reflection symmetry.

The area of a semicircle is the space enclosed by the semicircle. Since a semicircle is exactly half a circle, its formula can be obtained by dividing the area of a circle by 2.

As we know,

Area of a Circle = *πr*^{2}

Thus,

Area of a semicircle = *πr*^{2}/2, here *π* = 3.141, *r* = radius

The area of a semicircle is expressed in square units (m^{2}, cm^{2,} etc)

Let us solve an example to clear your concept.

**Find the area of a semicircle with a radius of 6 cm.**

Solution:

As we know,

Area (A) = πr^{2}/2, here π = 3.141, r = 6 cm

= 3.141 × (6)^{2}/2

= 56.538 cm^{2}

Using the above formula for calculating the area, we also find the radius of the semicircle if the area of the semicircle is known.

Let us solve a problem to clear your concept.

**The area of a semicircle is 555.55 cm ^{2}. Find the radius of the semicircle.**

Solution:

As we know,

Area (A) = πr^{2}/2, here area = 555.55 cm^{2}, π = 3.141

555.55 = 3.141 × r^{2}/2

r^{2} = 555.55 × 2/3.141

r^{2} = 353.74

r = 18.80 cm

The perimeter of a semicircle is the sum of half the circle’s circumference, plus the diameter of the semicircle. It is also called the circumference of a semicircle. Thus, it is not half the perimeter of a circle.

As the perimeter of a circle is given by 2πr or πd

So, the perimeter of the semicircle = ½ (2*πr*) + *d* =>* πr* + *d* =>* πr* + 2*r*, here π = 3.141, *r* = radius

or, ½ *πd* + *d*, here *π* = 3.141, *d* = diameter

The perimeter of a semicircle is expressed in units of m, cm, etc.

Let us solve an example to clear your concept.

**A semicircle has a diameter of 60 m. Find the perimeter of the semicircle.**

Solution:

As we know,

Perimeter (P) = ½ πd + d, here π = 3.141,d = 60 m

= (½ × 3.141 × 60 + 60) m

= 154.23 m

**The basketball court of your school has 2 semicircles at each end. The semicircles have 12 cm radii. What is the perimeter of one semicircle of the court?**

Solution:

As we know,

Perimeter (P) = πr + 2r, here π = 3.141, r = 12 cm

= (3.141 × 12) + (2 × 12) cm

= 61.69 cm

**Find the circumference of the semicircle whose diameter is 22 cm.**

Solution:

As we know,

Circumference is same as perimeter of a semicircle.

Thus,

Perimeter (P) = ½ πd + d, here π = 3.141,d = 22 cm

= (½ × 3.141 × 22 + 22) cm

= 56.55 cm

**A circle has a diameter of 16 m. Find the area and perimeter of a semicircle.**

Solution:

As we know,

Area (A) = πr^{2}/2, here π = 3.141, r** = **d/2 = 16/2 = 8 m

= 3.141 × (8)^{2}/2

= 100.51 cm^{2}

Again,

Perimeter (P) = ½ πd + d, here π = 3.141,d = 16 cm

= (½ × 3.141 × 16 + 16) cm

= 41.12 cm

**Michael has a circular-shaped garden outside his house with a radius of 6 yd. Now, he wants to fence exactly half of the garden. Calculate the perimeter he wants to fence.**

Solution:

As we know,

Perimeter (P) = πr + 2r, here π = 3.141, r = 6 yd

= (3.141 × 6 + 2 × 6) yd

= 30.846 yd

Hence, Michael will need to fence a perimeter of 30.846 yd

**Calculate the arc length of a semicircle with a diameter of 6 cm and a perimeter of 30 cm.**

Solution:

As we know,

The arc length of a semicircle can be obtained by subtracting the diameter of the semicircle from its perimeter.

Thus,

Arc Length (L) = Perimeter of the semicircle – Diameter of the semicircle

= (30 – 6) cm

= 24 cm

An inscribed angle of a semicircle is an angle formed by drawing a line from each endpoint of the diameter to a point on the semicircle arc.

Thus, an inscribed angle has a measure that is half the measure of the arc that subtends it. Since a semicircle is half of a circle the angle subtended by the arc that forms the semicircle measures 180°. Therefore, all inscribed angle of a semicircle is 180°/2 = 90° Thus, an angle inscribed in a semicircle is a right angle.

Last modified on August 3rd, 2023