Table of Contents
Last modified on February 26th, 2025
The slope-intercept form is one of the most common ways of representing a straight line. It is used when we need to find the linear equation given the slope and the y-intercept.
The slope-intercept form is given by:
y = mx + b
Here,
An example of a linear equation in the slope-intercept form is:
y = 4x – 1
Here, m = 4, and the y-intercept is at (0, -1)
The slope (m) represents the steepness of a line. It is measured by the change in y for every unit increase in x.
Mathematically,
Slope (m) = ${\dfrac{change \ in \ y}{change \ in \ x}}$
= ${\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}}$
Here,
(x1, y1) and (x2, y2) are two points on the line
The y-intercept (b) is the point where the line touches or crosses the y-axis. It is the value that y takes when x = 0
Let us consider a straight line with a slope m that intersects the y-axis at the point (0, b), where b is the y-intercept. Let (x, y) be an arbitrary point on the same line.
As we know, the slope (m) of a line is given by:
m = ${\dfrac{change \ in \ y}{change \ in \ x}}$ = ${\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}}$
Here, (x1, y1) = (0, b) and (x2, y2) = (x, y)
Now, by calculating m, we get
m = ${\dfrac{y-b}{x-0}}$
⇒ m = ${\dfrac{y-b}{x}}$
⇒ mx = y – b
⇒ y = mx + b, which is the slope-intercept form of a straight line
Now, let us determine the equation of a line passing through the points (2, 5) and (4, 9)
As we know, the slope-intercept form is y = mx + c
Here,
The slope is m = ${\dfrac{9-5}{4-2}=\dfrac{4}{2}=2}$
Now, to find the y-intercept, we use the point (2, 5)
y = mx + b
⇒ 5 = 2(2) + b (since m = 2)
⇒ 5 = 4 + b
⇒ b = 5 – 4
⇒ b = 1
Thus, the y-intercept is (0, 1), and the equation is y = 2x + 1
For graphing a linear equation in slope-intercept form, we follow the following points:
Let us plot y = 3x + 4 on the coordinate plane.
Here,
The y-intercept is 4
Thus, the coordinates of the y-intercept are (0, 4)
Now, to find another point, we use the slope m = 3
Starting with the point (0, 4), we move 3 units up (positive rise) and 1 unit to the right (positive run), and we get another point as (1, 7)
Now, plotting the points (0, 4) and (1, 7), we get
Note: If m = 0, the line is horizontal. For example, y = 4.
A line passes through the point (2, 5) and has a slope of 4. Write its equation in slope-intercept form.
As we know, the point-slope form of a line is y – y1 = m(x – x1)
Here,
The point is (x1, y1) = (2, 5)
The slope is m = 4
Now, the equation of a line is:
y – 5 = 4(x – 2)
⇒ y – 5 = 4x – 8
⇒ y = 4x – 8 + 5
⇒ y = 4x – 3
Thus, the equation of the line in slope-intercept form is: y = 4x – 3
If a line has an equation y = -2x + 7, determine its slope and y-intercept.
As we know, the slope-intercept form of a line is y = mx + b …..(i)
Given, y = -2x + 7 …..(ii)
Comparing (i) and (ii), we get
m = -2 and b = 7
Thus, the slope is -2, and the y-intercept is 7
Convert the equation ${y-4=\dfrac{3}{2}\left( x-6\right)}$ to slope-intercept form.
Given, ${y-4=\dfrac{3}{2}\left( x-6\right)}$
⇒ ${y-4=\dfrac{3x}{2}-\dfrac{18}{2}}$
⇒ ${y-4=\dfrac{3x}{2}-9}$
⇒ ${y=\dfrac{3x}{2}-9+4}$
⇒ ${y=\dfrac{3x}{2}-5}$
Thus, the equation of the line in slope-intercept form is: ${y=\dfrac{3x}{2}-5}$
Write the following equations in slope-intercept form.
a) 10x – 4y = 20
b) 5x + 2y = 12
a) Given, 10x – 4y = 20
⇒ -4y = -10x + 20
⇒ 4y = 10x – 20
⇒ y = ${\dfrac{10x}{4}-\dfrac{20}{4}}$
⇒ y = ${\dfrac{5x}{2}-5}$
Thus, the equation of the line in slope-intercept form is: y = ${\dfrac{5x}{2}-5}$
b) Given, 5x + 2y = 12
⇒ 2y = -5x + 12
⇒ y = ${-\dfrac{5x}{2}+\dfrac{12}{2}}$
⇒ y = ${-\dfrac{5x}{2}+6}$
Thus, the equation of the line in slope-intercept form is: y = ${-\dfrac{5x}{2}+6}$
Last modified on February 26th, 2025