Table of Contents
Last modified on July 19th, 2024
A proper fraction is a fraction in which the numerator is smaller than the denominator. Thus, the value of a proper fraction is always less than 1.
${\dfrac{2}{3}}$, ${\dfrac{5}{8}}$, ${\dfrac{11}{28}}$, ${\dfrac{3}{7}}$, ${\dfrac{4}{13}}$, and ${\dfrac{15}{48}}$ are a few examples of proper fraction.
We can easily visualize a proper fraction using pie charts or bar models.
For instance, if we divide a pie into two equal parts, the shaded 1 part represents the proper fraction ${\dfrac{1}{2}}$.
Similarly, dividing the pie into four equal parts, each part represents ‘quarter’ and is represented as ${\dfrac{1}{4}}$, which is also a proper fraction.
Unlike an improper fraction, a proper fraction never completes the whole. Thus, a proper fraction cannot be converted to an improper fraction and vice versa.
The value of a proper fraction always lies between 0 and 1, which can be easily represented on a number line.
Let us represent the fraction ${\dfrac{5}{8}}$ on a number line.
We first look at the denominator to represent a proper fraction on a number line. The denominator indicates the number of divisions we need to make between 0 and 1.
Now, marking the divisions based on the numerator of the fraction,
Here, the first interval is marked as ${\dfrac{1}{8}}$, the second is ${\dfrac{2}{8}}$, and so on, with the last mark being ${\dfrac{8}{8}}$, or 1.
The numerator indicates where we should mark to represent the given fraction. Here, the numerator is 5. Thus, we mark the fifth interval to represent ${\dfrac{5}{8}}$.
While adding proper fractions, we consider two cases based on the denominators: whether they are the same or different.
Adding proper fractions with the same denominator is straightforward: keeping the denominator the same, we simply add the numerators.
For example,
${\dfrac{2}{7}+\dfrac{4}{7}}$
= ${\dfrac{2+4}{7}}$
= ${\dfrac{6}{7}}$
When the fractions have different denominators, we find their LCM (Least Common Multiple) and then rewrite them as equivalent fractions using the LCM as a common denominator. Once the denominators are the same, we add the numerators.
For example,
${\dfrac{5}{8}+\dfrac{1}{4}}$
Here, the denominators are 8 and 4
Their LCM is 8
The denominator of the first fraction ${\dfrac{5}{8}}$ is 8 (which is the same as the LCM), while in the second fraction ${\dfrac{1}{4}}$ it is 4, which is different.
Now, we convert ${\dfrac{1}{4}}$ to an equivalent fraction with 8 as the denominator.
${\dfrac{1\times 2}{4\times 2}}$ = ${\dfrac{2}{8}}$
Thus, the sum is
${\dfrac{5}{8}+\dfrac{1}{4}}$
= ${\dfrac{5}{8}+\dfrac{2}{8}}$
= ${\dfrac{5+2}{8}}$
= ${\dfrac{7}{8}}$
Subtracting proper fractions follows the same principle as addition.
${\dfrac{4}{9}-\dfrac{2}{9}}$
= ${\dfrac{4-2}{9}}$
= ${\dfrac{2}{9}}$
Let us subtract ${\dfrac{1}{4}}$ from ${\dfrac{5}{8}}$
Here, the denominators are 8 and 4
Their LCM is 8
The denominator of the first fraction ${\dfrac{5}{8}}$ is 8 (which is the same as the LCM), while in the second fraction ${\dfrac{1}{4}}$ it is 4, which is different.
Now, we convert ${\dfrac{1}{4}}$ to an equivalent fraction with 8 as the denominator.
${\dfrac{1\times 2}{4\times 2}}$ = ${\dfrac{2}{8}}$
Thus, the difference is
${\dfrac{5}{8}-\dfrac{1}{4}}$
= ${\dfrac{5}{8}-\dfrac{2}{8}}$
= ${\dfrac{5-2}{8}}$
= ${\dfrac{3}{8}}$
To multiply proper fractions, we multiply the numerators and then the denominators together and, finally, simplify the result if needed.
For example,
${\dfrac{1}{2}\times \dfrac{5}{6}}$
= ${\dfrac{1\times 5}{2\times 6}}$
= ${\dfrac{5}{12}}$
To divide a fraction by another, we multiply the first fraction (dividend) by the reciprocal of the second fraction (divisor).
For example,
Let us divide ${\dfrac{1}{6}}$ by ${\dfrac{2}{3}}$
${\dfrac{1}{6}\div \dfrac{2}{3}}$
Here, the dividend is ${\dfrac{1}{6}}$ and the divisor is ${\dfrac{2}{3}}$
The reciprocal of ${\dfrac{2}{3}}$ is ${\dfrac{3}{2}}$
Now, multiplying ${\dfrac{1}{6}}$ by ${\dfrac{3}{2}}$, we get
${\dfrac{1}{6}\times \dfrac{3}{2}}$
= ${\dfrac{1\times 3}{6\times 2}}$
= ${\dfrac{3}{12}}$
= ${\dfrac{1}{4}}$
Basis | Proper Fraction | Improper Fraction |
---|---|---|
Numerators and denominators | The numerator is smaller than the denominator Numerator < Denominator | The numerator is greater than or equal to the denominator Numerator ≥ Denominator |
Value | Its value is always between 0 and 1 | Its value is always greater than or equal to 1 |
Examples | ${\dfrac{3}{4}}$, ${\dfrac{5}{12}}$, and ${\dfrac{3}{7}}$ | ${\dfrac{4}{3}}$, ${\dfrac{12}{5}}$, and ${\dfrac{7}{3}}$ |
When adding a mixed fraction and a proper fraction, we first convert the mixed fraction to an improper fraction and then add the given fractions. After getting the sum, we convert the result to a mixed fraction again.
For example,
${1\dfrac{2}{5}+\dfrac{3}{7}}$
= ${\dfrac{7}{5}+\dfrac{3}{7}}$
= ${\dfrac{7\times 7}{5\times 7}+\dfrac{3\times 5}{7\times 5}}$
= ${\dfrac{49+15}{35}}$
= ${\dfrac{64}{35}}$
= ${1\dfrac{29}{35}}$
Which one of the following examples represents a proper fraction?
${\dfrac{1}{8}}$, ${1\dfrac{5}{2}}$, ${\dfrac{9}{8}}$, and ${\dfrac{12}{5}}$
Here, ${\dfrac{1}{8}}$ represents a proper fraction.
Add the following proper fractions:
${\dfrac{1}{8}}$, ${\dfrac{2}{5}}$
Given ${\dfrac{1}{8}+\dfrac{2}{5}}$
= ${\dfrac{1\times 5}{8\times 5}+\dfrac{2\times 8}{5\times 8}}$
= ${\dfrac{5}{40}+\dfrac{16}{40}}$
= ${\dfrac{5+16}{40}}$
= ${\dfrac{21}{40}}$
Subtract ${\dfrac{1}{4}}$ from ${\dfrac{7}{12}}$
Here,
${\dfrac{7}{12}-\dfrac{1}{4}}$
= ${\dfrac{7}{12}-\dfrac{1\times 3}{4\times 3}}$
= ${\dfrac{7}{12}-\dfrac{3}{12}}$
= ${\dfrac{7-3}{12}}$
= ${\dfrac{4}{12}}$
= ${\dfrac{1}{3}}$
Last modified on July 19th, 2024