Table of Contents

Last modified on August 3rd, 2023

Trigonometric ratios are the ratios of the side lengths of a right-angled triangle. Three common trigonometric ratios are the sine (sin), cosine (cos), and tangent (tan). There are three more trigonometric ratios, cosecant (cosec), secant (sec), and cotangent (cot), that is, the inverse of sine, cosine, and tangent.

Thus, it is used to determine the ratios of any 2 sides of a right-angled triangle with respect to specific angles.

The value of these trigonometric ratios is calculated using the measure of any special acute angle Î¸ in a right-angled triangle.

The standard formulas for the given trigonometric ratios for Î¸ (where Î¸ is an acute angle) are:

**Sine (sin)**: It is the ratio of the opposite side (perpendicular side) to Î¸ to the hypotenuse

âˆ´ sin Î¸ = Opposite side/ Hypotenuse

**Cosine (cos)**: It is the ratio of the adjacent side to Î¸ to the hypotenuse

âˆ´ cos Î¸ = Adjacent side/ Hypotenuse

**Tangent (tan)**: It is the ratio of the opposite side to Î¸ to the side adjacent to Î¸

âˆ´ tan Î¸ = Opposite side/ Adjacent side

**Cosecant (cosec)**: It is the multiplicative inverse of sine

âˆ´ cosec Î¸ = 1/sin Î¸ = Hypotenuse /Opposite side

**Secant (sec)**: It is the multiplicative inverse of cosine

âˆ´ sec Î¸ = 1/cos Î¸ = Hypotenuse/ Adjacent side

**Cotangent (cot)**: It is the multiplicative inverse of tangent

âˆ´ cot Î¸ = 1/tan Î¸ = Adjacent side/Opposite side

In the given right-triangle ABC, the trigonometric ratios are shown:

Thus, with respect to âˆ C, the ratios of trigonometry are:

- sine C = Side opposite to âˆ C/Hypotenuse = AB/AC
- cos C = Side adjacent to âˆ C/Hypotenuse = BC/AC
- tan C = Side opposite to âˆ C/Side adjacent to âˆ ) = AB/BC = sin âˆ C/cos âˆ C
- cosec C= 1/sin C = Hypotenuse/ Side Opposite to âˆ C = AC/AB
- sec C = 1/cos C = Hypotenuse/ Side Opposite to âˆ C = AC/BC
- cot C = 1/tan C = Side adjacent to âˆ C/Side opposite to âˆ C = BC/AB

All the ratios written above for âˆ C in all possible right triangles will be the same. The same being with âˆ A

The word sohcahtoa can be used to remember the trigonometric ratio formulas of sine, cosine, and tangent:

Acronyms | Descriptions | Formulas |
---|---|---|

SOH | Sine is Opposite over Hypotenuse | Sin Î¸ = Opposite side/ Hypotenuse |

CAH | Cosine is Adjacent over Hypotenuse | Cos Î¸ = Adjacent side/ Hypotenuse |

TOA | Tangent is Opposite over Adjacent | Tan Î¸ = Opposite side/ Adjacent side |

The trigonometric ratios table displays the values of trigonometric ratios for the standard angles 0Â°, 30Â°, 45Â°, 60Â°, and 90Â° used in several trigonometric calculations.

Several trigonometric ratios identities make our calculations simpler such as:

- sin
^{2}Î¸ + cos^{2}Î¸ = 1 - 1 + tan
^{2}Î¸ = sec^{2}Î¸ - 1 + cot
^{2}Î¸ = cosec^{2}Î¸

There are also some variations of the above 3 identities, which are nothing but rearranging the ones given above.

The complement of an angle Î¸ is (90Â° – Î¸). Accordingly, the trigonometric ratios of complementary angles are:

- sin (90Â°- Î¸) = cos Î¸
- cos (90Â°- Î¸) = sin Î¸
- cosec (90Â°- Î¸) = sec Î¸
- sec (90Â°- Î¸) = cosec Î¸
- tan (90Â°- Î¸) = cot Î¸
- cot (90Â°- Î¸) = tan Î¸

The sum, difference, and product trigonometric ratios identities are:

- sin (A + B) = sin A cos B + cos A sin B
- sin (A – B) = sin A cos B – cos A sin B
- cos (A + B) = cos A cos B – sin A sin B
- cos (A – B) = cos A cos B + sin A sin B
- tan (A + B) = (tan A + tan B)/ (1 – tan A tan B)
- tan (A – B) = (tan A – tan B)/ (1 + tan A tan B)
- cot (A + B) = (cot A cot B – 1)/(cot B – cot A)
- cot (A – B) = (cot A cot B + 1)/(cot B – cot A)
- 2 sin Aâ‹…cos B = sin(A + B) + sin(A – B)
- 2 cos Aâ‹…cos B = cos(A + B) + cos(A – B)
- 2 sin Aâ‹…sin B = cos(A – B) – cos(A + B)

The half, double, and triple-angles trigonometric ratios identities

- sin 2Î¸ = 2 sinÎ¸ cosÎ¸
- cos 2Î¸ = cos
^{2}Î¸ – sin^{2}Î¸ = = 2 cos^{2}Î¸ â€“ 1 = 1 – 2 sin^{2}Î¸ = (1 – tan^{2}Î¸)/(1 + tan^{2}Î¸) - sec 2Î¸ = sec
^{2 }Î¸/(2-sec^{2}Î¸) - cosec 2Î¸ = (sec Î¸. cosec Î¸)/2
- cot 2Î¸ = (cot Î¸ – tan Î¸)/2
- sin 3Î¸ = 3sin Î¸ – 4sin
^{3}Î¸ - cos 3Î¸ = 4cos
^{3}Î¸ – 3cos Î¸ - tan 3Î¸ = (3tanÎ¸ – tan
^{3}Î¸)/(1 – 3tan^{2}Î¸)

**Find the value of tan Î¸ if sin Î¸ = 14/5 and cos Î¸ =6/9**

Solution:

As we know,

tan Î¸ = sin Î¸/cos Î¸, here sin Î¸ = 14/5 and cos Î¸ = 6/9

= (14/5)(6/9)

= 63/15

Last modified on August 3rd, 2023

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