Table of Contents
Last modified on August 3rd, 2023
The mid-segment of a trapezoid is the line segment mid-way between its two bases. It is also called the median or the midline.
How many mid-segments does a trapezoid have?
A trapezoid has only one mid-segment since it has only 2 parallel sides and 2 non parallel sides.
The mid-segment bisects the non parallel sides. In other words, a mid-segment is the mid-way between the two bases.
The next segment will help you find the mid-segment of a trapezoid.
The basic formula to find the mid-segment of a trapezoid is given below:
Find the length of the mid-segment of the trapezoid given.
As we know,
Mid-segment (M) = ½(a + b), here a = 23 cm, b = 14 cm
∴ M = ½(23 + 14)
= 18.5 cm
In trapezoid PQRS, what is the length of mid-segment XY.
As we know,
Mid-segment (M) = ½(27 + 12), here a = 27 cm, b = 12 cm
∴ M = ½(27 + 12)
= 19.5 cm
The trapezoid mid-segment theorem states that a line connecting the midpoints of the non-parallel sides (legs) is parallel to the bases. It measures half the sum of lengths of the bases.
Prove that the line connecting the midpoints of the legs of a trapezoid ABCD is parallel to the bases and half the sum of lengths of the bases.
EF ∥AD, EF ∥BC
AB ∥ CD, AE ≅ EB, DF ≅ FC
AF and BC produced to point P
Statement | Reason |
---|---|
∠ADF ≅ ∠FCP | AAS (Angle-Angle-Side) postulate, alternate angles |
∠AFD ≅ ∠CFP | AAS (Angle-Angle-Side) postulate, opposite angles |
ΔADF ≅ ΔFCP | AAS postulate |
EF ∥BP ∥BC EF = ½ BP | EF is mid-segment of ΔABP |
EF = ½(BC + CP) | CP ≅ AD, SS postulate, ΔADF ≅ ΔFCP |
EF = ½(AD + BC) | AD ≅ CP Hence proved |
EF ∥AD, EF ∥BC | AD ∥BC, given Hence proved |
Last modified on August 3rd, 2023